{"id":162031,"date":"2025-06-04T09:25:58","date_gmt":"2025-06-04T06:25:58","guid":{"rendered":"https:\/\/vr.lv\/main-factors-that-accelerate-lithium-battery-degradation\/"},"modified":"2025-06-04T09:47:39","modified_gmt":"2025-06-04T06:47:39","slug":"main-factors-that-accelerate-lithium-battery-degradation","status":"publish","type":"post","link":"https:\/\/vr.lv\/lt\/main-factors-that-accelerate-lithium-battery-degradation\/","title":{"rendered":"Kaip pailginti telefon\u0173, plan\u0161etini\u0173 kompiuteri\u0173 ir kit\u0173 \u012frengini\u0173 su li\u010dio baterijomis tarnavimo laik\u0105"},"content":{"rendered":"\n

Kaip pailginti telefon\u0173, plan\u0161etini\u0173 kompiuteri\u0173 ir kit\u0173 \u012frengini\u0173 su li\u010dio baterijomis tarnavimo laik\u0105.

Pagrindiniai veiksniai, kurie pagreitina li\u010dio baterij\u0173 d\u0117v\u0117jim\u0105si:<\/h4>\n\n\n\n
\u2705 Auk\u0161ta temperat\u016bra<\/strong>
\u2013 Pavojingiausias veiksnys!
\u2013 Nuolatin\u0117 temperat\u016bra vir\u0161 30\u201335 \u00b0C<\/strong> spartina baterijos sen\u0117jim\u0105.
\u2013 Ypa\u010d pavojinga prie apkrovos (\u012fkrovimo\/i\u0161krovimo)<\/strong>: prie 40 \u00b0C talpa ma\u017e\u0117ja grei\u010diau, o prie 60 \u00b0C \u2013 akimirksniu.
\u2013 Pavyzdys:<\/strong> vasar\u0105 automobilyje paliktas telefonas (viduje gali b\u016bti 60\u201370 \u00b0C).<\/p>\n\n\n\n
\u2705 Gilus i\u0161krovimas (\u017eemiau 3,0 V vienam elementui)<\/strong>
\u2013 Gilus i\u0161krovimas iki 0% sukelia negr\u012f\u017etamus cheminius poky\u010dius<\/strong> elektrolite ir anode.
\u2013 Geriau nei\u0161krauti iki galo<\/strong> \u2013 optimalu, kai lieka 10\u201320%.<\/p>\n\n\n\n
\u2705 Nuolatinis \u012fkrovimas iki 100%<\/strong>
\u2013 Baterijos laikymas 100% (ypa\u010d prie apkrovos) yra \u017ealingas.
\u2013 100% metu \u012ftampa yra apie 4,2 V, kas sukelia didel\u012f chemin\u012f stres\u0105<\/strong>.
\u2013 Ilgesniam tarnavimo laikui \u2013 \u012fkraukite iki 80\u201390% ir venkite i\u0161krovimo \u017eemiau 20\u201330%.<\/p>\n\n\n\n
\u2705 Daug \u012fkrovimo\/i\u0161krovimo cikl\u0173<\/strong>
\u2013 Kiekvienas ciklas yra \u201csm\u016bgis\u201d baterijai.
\u2013 Paprastai li\u010dio baterijos skirtos ~500\u2013800 piln\u0173 cikl\u0173<\/strong> iki 80% talpos.
\u2013 Da\u017eni gil\u016bs ciklai trumpina tarnavimo laik\u0105.<\/p>\n\n\n\n
\n\n\n\n
Papildomi veiksniai<\/h4>\n\n\n\n
\u26a0\ufe0f Da\u017enas greitas \u012fkrovimas<\/strong>
\u2013 Greitas \u012fkrovimas (20\u201330 W) pakelia temperat\u016br\u0105, tod\u0117l spartina baterijos d\u0117v\u0117jim\u0105si.
\u2013 Ypa\u010d jei n\u0117ra gero au\u0161inimo.<\/p>\n\n\n\n
\u26a0\ufe0f \u017dema temperat\u016bra<\/strong>
\u2013 \u017dema temperat\u016bra (<0 \u00b0C) tiesiogiai nepa\u017eeid\u017eia baterijos, bet \u012fkraunant \u0161altyje gali susidaryti li\u010dio metalo danga<\/strong>.
\u2013 Po to baterija praranda talp\u0105, padid\u0117ja vidin\u0117 var\u017ea.<\/p>\n\n\n\n
\n\n\n\n
I\u0161vada: kaip pailginti tarnavimo laik\u0105?<\/h4>\n\n\n\n
\u2013 Venkite perkaitimo (nepalikite saul\u0117je, ne\u012fkraukite kar\u0161tyje).
\u2013 Nei\u0161kraukite iki nulio ir nelaikykite visada pilnai \u012fkrautos.
\u2013 Jei \u012fmanoma, naudokite \u201cbaterijos tausojimo re\u017eim\u0105\u201d (daugelyje \u012frengini\u0173 \u012fkrovimas iki 80%).
\u2013 Venkite greito \u012fkrovimo, jei tai n\u0117ra b\u016btina.
\u2013 \u012ekraukite esant vidutinei temperat\u016brai (geriausia 20\u201325 \u00b0C<\/strong>).<\/p>\n\n\n\n
\u012esigykite mobil\u0173j\u012f telefon\u0105, plan\u0161etin\u012f kompiuter\u012f, el. knyg\u0173<\/a> skaitytuv\u0105 ar bet koki\u0105 kit\u0105 prek\u0119 m\u016bs\u0173 svetain\u0117je. <\/p>\n\n\n\n
D\u017eiaugiam\u0117s kiekvienu j\u016bs\u0173 u\u017esakymu. A\u010di\u016b, kad perskait\u0117te \u0161\u012f straipsn\u012f! Tikim\u0117s, kad jis buvo jums naudingas. =)<\/p>\n","protected":false},"excerpt":{"rendered":"
Kaip pailginti telefon\u0173, plan\u0161etini\u0173 kompiuteri\u0173 ir kit\u0173 \u012frengini\u0173 su li\u010dio baterijomis tarnavimo laik\u0105. Pagrindiniai veiksniai, kurie pagreitina li\u010dio baterij\u0173 d\u0117v\u0117jim\u0105si:<\/p>\n","protected":false},"author":1,"featured_media":162026,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_relevanssi_hide_post":"","_relevanssi_hide_content":"","_relevanssi_pin_for_all":"","_relevanssi_pin_keywords":"","_relevanssi_unpin_keywords":"","_relevanssi_related_keywords":"","_relevanssi_related_include_ids":"","_relevanssi_related_exclude_ids":"","_relevanssi_related_no_append":"","_relevanssi_related_not_related":"","_relevanssi_related_posts":"","_relevanssi_noindex_reason":"","footnotes":""},"categories":[3521,3523],"tags":[],"class_list":["post-162031","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-news","category-news-lt"],"aioseo_notices":[],"aioseo_head":"\n\t\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t